A painter uses $\frac{3}{5}$ of a can of paint to cover one wall of a house. How many cans of paint will he need to cover 7 such walls?

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Solution

Given
$∵$ To cover one wall paint used $= \frac{3}{5}$ of can

$∴$ To cover $7$ wall paint used $= \frac{3}{5} \times 7$

$= \frac{21}{5}$

$= 4 \frac{1}{5}$

$= 4$ can and $= \frac{1}{5}$ of a can

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A painter uses 35 of a can of paint to cover one wall of a house. How many cans of paint will he need to cover 7 such walls?

Given ∵ To cover one wall paint used =35 of can∴ To cover 7 wall paint used =35×7=215=415=4 can and =15 of a can

A painter uses $\frac{3}{5}$ of a can of paint to cover one wall of a house. How many cans of paint will he need to cover 7 such walls?

Given
$∵$ To cover one wall paint used $= \frac{3}{5}$ of can

$∴$ To cover $7$ wall paint used $= \frac{3}{5} \times 7$

$= \frac{21}{5}$

$= 4 \frac{1}{5}$

$= 4$ can and $= \frac{1}{5}$ of a can