Question

A painting $40cm$ long and $28cm$ wide is pasted on a cardboard such that there is a margin of $2cm$ along each of its sides. Find the area of the margin.

Answer 1

Let $ABCD$ be the painting and $PQRS$ be the cardboard.

Therefore, length of the painting $=DC=40cm$ and

breadth of the painting $BC=28cm$

Therefore, area of the painting $ABCD=DC\times BC$

$=40\times 28$

$=1120c{m}^2$

Since margin is of $2cm$, therefore,

Length of cardboard $SR=40+2\times =44cm$ and

Breadth of the rectangle $RQ=28+2\times 2=32cm$

Therefore, area of $PQRS=QR\times SR$

$=44\times 32$

$=1408c{m}^2$

Therefore area of the margin $=$ Area of $PQRS-$ Area of $ABCD$

$=1408-1120$

$=288c{m}^2$