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Standard VIII

Physics

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A parachute o...

Question

A parachute of mass $m$ starts coming down with a constant acceleration $a$ . Determine the ballast mass to be released from the parachute to have an upward acceleration of same magnitude. Neglect air drag.

\frac{2 m a}{a + g}

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\frac{m a}{a - g}

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\frac{m a}{a + g}

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\frac{2 m a}{a - g}

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Solution

The correct option is A $\frac{2 m a}{a + g}$
Let the upward thrust on parachute $= T$ .
now , $m a = m g - T . . . . (1)$
If $m^{'}$ be the mass to be released, then
$(m - m^{'}) a = T - (m - m^{'}) g . . . . . (2)$
$(1) + (2), 2 m a - m^{'} a = m^{'} g$
or $2 m a = m^{'} (g + a) \Rightarrow m^{'} = \frac{2 m a}{g + a}$

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A parachute of mass m starts coming down with a constant acceleration a. Determine the ballast mass to be released from the parachute to have an upward acceleration of same magnitude. Neglect air drag.

The correct option is A 2maa+gLet the upward thrust on parachute =T.now , ma=mg−T....(1)If m′ be the mass to be released, then(m−m′)a=T−(m−m′)g.....(2)(1)+(2),2ma−m′a=m′gor 2ma=m′(g+a)⇒m′=2mag+a

A parachute of mass $m$ starts coming down with a constant acceleration $a$ . Determine the ballast mass to be released from the parachute to have an upward acceleration of same magnitude. Neglect air drag.