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Question

# A parachutist after bailing out falls for 10 s without friction. When the parachute opens he descends with an acceleration of 2 m/s2 against his direction and reached the ground with 4 m/s. From what height he has dropped himself? (g=10 m/s2)

A
500 m
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B
2496 m
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C
2996 m
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D
4296 m
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Solution

## The correct option is A 2996 mu=gt⇒u=10gh1=12gt2h2=v2−u2−2atotal height =h1+h2v=gt1(100)2=u2+2×10S1v=10×10=100m/s.[S1=500mt]4=100−2t2 t2=48sec⇒S2=100t2−1/2×2t22 =4800−(48)2 =2496 mt.S1+S2=2996 mt

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