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Question

A parachutist after bailing out falls for 10 s without friction. When the parachute opens he descends with an acceleration of 2 m/s2 against his direction and reached the ground with 4 m/s. From what height he has dropped himself? (g=10 m/s2)

A
500 m
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B
2496 m
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C
2996 m
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D
4296 m
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Solution

The correct option is A 2996 m
u=gtu=10g
h1=12gt2
h2=v2u22a
total height =h1+h2

v=gt1(100)2=u2+2×10S1
v=10×10=100m/s.[S1=500mt]
4=1002t2
t2=48sec
S2=100t21/2×2t22
=4800(48)2
=2496 mt.
S1+S2=2996 mt

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