A parachutist of weight $w$ strikes the ground and comes to rest with an upward acceleration of magnitude $3 g$ . Force exerted on him by the ground during landing is:

2 w

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3 w

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4 w

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5 w

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Solution

The correct option is B $4 w$
We find the parachute landing to rest and at this juncture the force exerted would be the $(g + a)$ , that is, both acceleration due to gravity and upward acceleration.
Upward resultant acceleration is $3 g$ and the apparent acceleration on parachutist $= 3 g + g = 4 g$
Force on parachutist $= m \times 4 g$ $= 4 m g = 4 w$
Thus, the parachutist exerts a force of $4 w$ during landing.

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A parachutist of weight w strikes the ground and comes to rest with an upward acceleration of magnitude 3g. Force exerted on him by the ground during landing is:

A parachutist of weight $w$ strikes the ground and comes to rest with an upward acceleration of magnitude $3 g$ . Force exerted on him by the ground during landing is: