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Standard XII

Physics

Second Law of Motion

A parachutist...

Question

A parachutist with total weight $75 k g$ drops vertically onto a sandy ground with a speed of $2 m s^{- 1}$ and comes to a halt over a distance of $0.25 m$ . The average force from the ground on her is close to

600 N

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1200 N

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1350 N

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1950 N

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Solution

The correct option is B $600 N$
Initial velocity while dropping on the ground u=2m/s.
Parachutist was brought to rest within s=0.25 m
Therefore retardation f : $u^{2} = 2 f s; f = \frac{u^{2}}{2 s} = 8 m / s^{2}$
Averarage force from ground on her close is F=mf=600 N

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A parachutist with total weight 75kg drops vertically onto a sandy ground with a speed of 2ms−1 and comes to a halt over a distance of 0.25m. The average force from the ground on her is close to

The correct option is B 600NInitial velocity while dropping on the ground u=2m/s. Parachutist was brought to rest within s=0.25 m Therefore retardation f : u2=2fs;f=u22s=8m/s2Averarage force from ground on her close is F=mf=600 N

A parachutist with total weight $75 k g$ drops vertically onto a sandy ground with a speed of $2 m s^{- 1}$ and comes to a halt over a distance of $0.25 m$ . The average force from the ground on her is close to

The correct option is B $600 N$
Initial velocity while dropping on the ground u=2m/s.
Parachutist was brought to rest within s=0.25 m
Therefore retardation f : $u^{2} = 2 f s; f = \frac{u^{2}}{2 s} = 8 m / s^{2}$
Averarage force from ground on her close is F=mf=600 N