Question

# A paralle plate capacitor of capacitance $$90$$ pF is connected to a battery of emf $$20$$V. If a dielectric material of dielectric constant K$$=\displaystyle\frac{5}{3}$$ is inserted between the plates, the magnitude of the induced charge will be.

A
2.4 n C
B
0.9 n C
C
1.2 n C
D
0.3 n C

Solution

## The correct option is B $$1.2$$ n CFor parallel plate capacitor$$Q=CV$$Initial charge $$Q_{i}=90pf\times 20V=1.8nC$$When dielectric material is inserted$$C=KC$$Final charge $$Q_{f}=(KC)V=\frac{5}{3}\times 90pF\times 20v$$=$$3nC$$Induced charge =$$Q{_f}-Q_{i}$$                              $$=3-1.8=1.2nC$$PhysicsNCERTStandard XII

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