A parallel beam of light $λ = 5000 A^{o}$ falls normally on a single narrow slit of width $0.001 m m$ . The light is focused by a convex lens on a screen placed in the focal plane. The first minimum will be formed for the angle of diffraction are equal to:

0^{0}

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15^{0}

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30^{0}

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50^{0}

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Solution

The correct option is C $30^{0}$
Let the angle be $θ$
$d s i n θ = λ$
$s i n θ = \frac{500 n m}{0.001 m m} = 0.5$
$θ = 30^{0}$
option $C$ is correct .

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A parallel beam of light λ=5000Ao falls normally on a single narrow slit of width 0.001mm. The light is focused by a convex lens on a screen placed in the focal plane. The first minimum will be formed for the angle of diffraction are equal to:

The correct option is C 300Let the angle be θdsinθ=λsinθ=500nm0.001mm=0.5θ=300option C is correct .

A parallel beam of light $λ = 5000 A^{o}$ falls normally on a single narrow slit of width $0.001 m m$ . The light is focused by a convex lens on a screen placed in the focal plane. The first minimum will be formed for the angle of diffraction are equal to:

The correct option is C $30^{0}$
Let the angle be $θ$
$d s i n θ = λ$
$s i n θ = \frac{500 n m}{0.001 m m} = 0.5$
$θ = 30^{0}$
option $C$ is correct .