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Question

A parallel beam of light of wavelength 6000 0A gets diffracted by a single slit of width 0.3 mm. The angular position of the first minima of diffracted light is

A
2×103rad
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B
3×103rad
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C
1.8×103rad
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D
6×103rad
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Solution

The correct option is A 2×103rad
Here, λ=60000A=6000×1010m=6×107ma0.3mm=0.3×104m=3×104m

For first minima, asinθ=λ where a is the slit widht
sinθ=λa=6×1073×104=2×103

As sinθ is very small

θsinθ=2×103rad

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