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Question

A parallel plate capacitor having air as dielectric medium is charged by a potential difference of V volt. After disconnecting the battery, the distance between the plates of the capacitor is increased using an insulated handle. As a result, potential difference between the plates

A
Increases
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B
Does not change
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C
Becomes zero
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D
Decreases
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Solution

The correct option is D Increases

When the battery is disconnected, the charge will remain same in any case. Capacitance of a parallel plate capacitor is given by
C=ε0A/d
When d is increased, capacitance will decreases and because the charge remains the same, so according to
q=CV,
the voltage will increase,

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