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Question

# A parallel plate capacitor with a slab of dielectric constant 3 filling the whole space between the plates is charged to certain potential and isolated. Then the slab is drawn out and another slab of equal thickness but dielectric constant 2 is introduced between the plates. The ratio of the energy stored in the capacitor later to that stored initially is?

A
2:3
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B
3:2
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C
4:9
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D
9:4
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Solution

## The correct option is B 2:3Capacity of plate when K=3 Ck=3=E03Ad-------(1)Again capacity of the plate when K=2 Ck=2=E02Ad-------(2)Dividing 2 and 1 we get The ratio of the energy stored in the capacitor later to stored initially=E02AdE03Ad=23

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