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Question

A particle covers $$ 50 m$$ distance when projected with an initial speed. On the same surface, when projected with double the initial speed  it will cover a distance of :



A
100 m
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B
150 m
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C
200 m
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D
250 m
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Solution

The correct option is C 200 m
In projectile motion,
Range, $$R=\dfrac{u^2sin2\theta}{g}=50m$$  (Given)
Now, Initial speed is $$u'=2u$$
$$R'=\dfrac{4u^2sin2\theta}{g}=4\times 50$$
$$R'=200m$$
The correct option is C.

1425236_1060043_ans_3082bbe24e1843c2af47bc22be03d8a3.png

Physics

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