Question

# A particle covers $$50 m$$ distance when projected with an initial speed. On the same surface, when projected with double the initial speed  it will cover a distance of :

A
100 m
B
150 m
C
200 m
D
250 m

Solution

## The correct option is C 200 mIn projectile motion,Range, $$R=\dfrac{u^2sin2\theta}{g}=50m$$  (Given)Now, Initial speed is $$u'=2u$$$$R'=\dfrac{4u^2sin2\theta}{g}=4\times 50$$$$R'=200m$$The correct option is C.Physics

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