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Question

A particle executes SHM with amplitude 0.2m and time period 24 sec. The time required by it to move from mean position to a point 0.1 m from the mean position is:


A

12 sec

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B

3 sec

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C

2 sec

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D

8 sec

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Solution

The correct option is C

2 sec


Particle starts from mean position hence equation of motion used will be of sin

x=A sinωt [ϕ=0]

0.1=0.2sin2πtT

sinπ6=sinπt12

t = 2 sec

Note: Particle starts from mean position use

x=A sin ωt

If particle starts from any position except mean, use

x=A cos(ωt+ϕ)


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