A particle executing simple harmonic motion has an angular frequency of $6.28 s^{- 1}$ and amplitude of $10 c m$ . The maximum acceleration of the particle is :

1 m / s^{2}

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4 m / s^{2}

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2 m / s^{2}

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8 m / s^{2}

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Solution

The correct option is B $4 m / s^{2}$
Maximum acceleration $= (a n g u l a r f r e q u e n c y)^{2} \times$ amplitude
$== (6.28)^{2} \times 10 = (39.4 \times 10) \approx 400 c m / s^{2} = 4 m / s^{2}$

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