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Question

A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance s1 in the first 10 seconds and distance s2 in the next 10 second then:

A
s2=s1
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B
s2=2s1
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C
s2=3s1
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D
s2=4s1
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Solution

The correct option is C s2=3s1
Distance traveled in first 10seconds

S1=ut+12at2=0t+12a102=50a

Total distance traveled in 20 seconds =
S=ut+12at2=0t+12a2062=200a

Distance traveled from 10s to 20s=S2=200a50a=150a
Hence answer is C.


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