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Standard IX

Physics

Distance and Displacement

A particle ha...

Question

A particle has a displacement of $12 m$ towards east then $5 m$ towards north and then $6 m$ vertically upwards. The resultant displacement is

10.04 m

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12.10 m

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14.32 m

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12.6 m

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Solution

The correct option is B $14.32 m$
These are 3 perpendicular directions. Hence , total displacement = $\sqrt{(5^{2} + 12^{2} + 6^{2})}$ = $14.32 m$

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The correct option is B 14.32 m These are 3 perpendicular directions. Hence , total displacement = √(52+122+62) = 14.32 m

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The correct option is B $14.32 m$
These are 3 perpendicular directions. Hence , total displacement = $\sqrt{(5^{2} + 12^{2} + 6^{2})}$ = $14.32 m$