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Question

A particle has an initial velocity of $$3\hat{i}+4\hat{j}$$ and an acceleration of $$0.4\hat{i}+0.3\hat{j}$$. Its speed after $$10s$$ is?


Solution

the initial velocity is give as $$vi = 3i + 4j$$ 

the acceleration is $$a = 0.4i + 0.3j$$ 

and the time elapsed is$$ t = 10s$$

now final velocity after$$ 10s$$ is $${ v }_{ f }=(3i+4j)\frac { m }{ s } +10s(0.4i+0.3j)\frac { m }{ s } $$

$${ v }_{ f }=7i+7j$$

 $$v=\sqrt { (7i)^{ 2 })+(7j)) } =7\sqrt { 2 } $$


Physics

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