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Question

A particle having charge q and mass m is released from rest at origin, in a region with uniform electric field of magnitude E which is directed along the positive xaxis. The speed of the particle as it crosses point x=x0 will be -

​​​​​​​[0.77 Mark]

A
qEx0m
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B
2qEx0m
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C
qEmx0
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D
4qEx0m
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Solution

The correct option is B 2qEx0m
From work-energy theorem,

Work done by electric field = Change in kinetic energy

Force×displacement=K.EfK.Ei

qEx0=12mv20

v=2qEx0m

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