CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A particle is moving in a circle of radius $$10$$ cm with uniform speed, completing the circle in $$4$$ s. Find the magnitude of its acceleration.


A
πcm/s2
loader
B
2.5π2cm/s2
loader
C
π2cm/s2
loader
D
2πcm/s2
loader

Solution

The correct option is B $$2.5 \pi^2 cm/s^2$$
Answer is B.
The distance covered in completing the circle $$2\pi r=2\pi \times 10cm$$. 
The linear speed is $$v = 2\pi r/t = \displaystyle \frac{2\pi \times 10\, cm}{4\, s} = 5 \pi\, cm/s$$
The acceleration is $$a = \displaystyle \frac{v^{2}}{r} = \frac{(5\pi cm/s)^{2}}{10\, cm} = 2.5\, \pi^2\, cm/s^{2}$$.
Hence, the magnitude of its acceleration is $$= 2.5\, \pi^2\, cm/s^{2}$$.

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image