Question

# A particle is moving in a circle of radius $$10$$ cm with uniform speed, completing the circle in $$4$$ s. Find the magnitude of its acceleration.

A
πcm/s2
B
2.5π2cm/s2
C
π2cm/s2
D
2πcm/s2

Solution

## The correct option is B $$2.5 \pi^2 cm/s^2$$Answer is B.The distance covered in completing the circle $$2\pi r=2\pi \times 10cm$$. The linear speed is $$v = 2\pi r/t = \displaystyle \frac{2\pi \times 10\, cm}{4\, s} = 5 \pi\, cm/s$$The acceleration is $$a = \displaystyle \frac{v^{2}}{r} = \frac{(5\pi cm/s)^{2}}{10\, cm} = 2.5\, \pi^2\, cm/s^{2}$$.Hence, the magnitude of its acceleration is $$= 2.5\, \pi^2\, cm/s^{2}$$.Physics

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