Question

# A particle is moving with velocity (^i+2^j+3^k) m/s. A plane mirror exists in the x - y plane. The mirror has a velocity (^i+2^j) m/s. Velocity of the image (in m/s) is:

A
^j+^k
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
^i+2^j3^k
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
^j^k
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B ^i+2^j−3^kSince the mirror is in x-y plane, only the z-component of the velocity of the image with respect to the mirror will be reversed as compared to the velocity of the object with respect to the mirror Hence velocity of the object with respect to the mirror →vom=→vo−→vm=(^i+2^j+3^k)−(^i+2^j) →vom=3^k Hence velocity of the image with respect to the mirror →vim=−3^k →vi=→vm−3^k →vi=^i+2^j−3^k

Suggest Corrections
1
Related Videos
Moving Object and Mirror
PHYSICS
Watch in App