CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A particle is projected from the ground at an angle of 60 with the horizontal with speed u=20 m/s. The radius of curvature of the path of the particle, when its velocity makes an angle of 30 with the horizontal is (g=10 m/s2)

A
10.6 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
12.8 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
15.4 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
24.2 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 15.4 m
Radius of curvature =(Velocity)2Radial Acceleration

From the figure, we get
Radial acceleration =gcosθ
Radius of curvature r=v2gcosθ

Since, there is no acceleration along horizontal direction
vcos30=20cos60
v=203 m/s

r=2023×10×32=15.4 m

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Falling Balls in Disguise
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon