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A particle is projected vertically upwards with speed 20 m/s from top of a tower of height 20 m as shown in figure. Given B is top most point of trajectory and C is at same height as A :
Column - IColumn - II(A)ratio of maximum height from ground (BD)(P)12to the initial height from ground (AD)is(B)ratio of distance travelled in 1st second to(Q)13the distance travelled in 2nd second is(C)ratio of initial speed at A to the final(R)1just before reaching to ground (D) is(D)ratio of time taken from A to C and time(S)2taken from A to B is(T)4(U)3
Which of the following option has the incorrect combination considering column-I and column-II


Your Answer
A
AS
Correct Answer
B
BQ
Your Answer
C
CP
Your Answer
D
DS

Solution

The correct option is B BQ
(I) AB= maximum height =v22g=20×202×10=20 m
BDAD=20+2020=2

(II) s(1st)s(2nd)=20×112×10×1220[15]=155=3

(III) vAvD=20202+2×10×20=20202=12

(IV) tACtAB=2tABtAB=2

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