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Question

A particle is released from rest at origin. It moves under influence of potential field $$U=x^{2}-3x$$, kinetic energy at $$x=2$$ is:


A
2 J
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B
1 J
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C
1.5 J
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D
0 J
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Solution

The correct option is A $$2\ J$$
F=ma=-$$\dfrac{dU}{dx}$$
mv$$\dfrac{dv}{dx}$$=$$-2x+3$$
on integration
$$m\dfrac{v^2}{2}=-x^2+3x$$
$$KE=3\times 2-2^2=2J$$



Physics

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