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Question

A particle is thrown vertically upwards. Its velocity at half of the maximum height is 20 m/s. Then the maximum height attained by it will be: (Take g=10 m/s2)

A
40 m
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B
25 m
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C
10 m
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D
45 m
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Solution

The correct option is A 40 m
Let the maximum height attained by particle be H
Taking vertically upward direction as +ve and applying kinematic equation,
v2=u2+2as ...(i)

where at maximum height v=0,
Displacement of particle from half the maximum height to maximum height is s=+H2
& velocity of particle at distance equal to half of maximum height is u=+20 m/s
Also, a=g=10 m/s2

Putting all values in Eq (i),
(0)2=(20)22×10×(H2)
or 400=10H
H=40 m

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