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Question

A particle is thrown with velocity of um/s. it passes A and B as shown in the figure at time t1=1s and t2=3s. The value of u is (g=10m/s2)
1275826_c49246fc0a9a40fda683f30b3bcb12ac.png

A
20 m/s
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B
10 m/s
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C
5 m/s
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D
40 m/s
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Solution

The correct option is A 20 m/s
Suppose the height travelled by ball in time
t1 & t2 is 'h' and speed of projection is U.
Then using relation
S=Ut+1/2at2
h=Ut112gt21 __ (1)
h=Ut212gt22 __ (2)
so equating both equations
Ut112gt21=Ut212gt22
solving above we get
U=g(t21t22)2(t1t2)=g(t1+t2)2
So, U=10(1+3)2
U=20m/s

1194743_1275826_ans_db4afb1c258640958ebc92efe6ee5044.jpeg

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