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Question

A particle moves, along a straight line OX. At a time t (in second), the position x (in metre) of the particle from O is given by x=40+12tt3. How much distance particle covers before coming to rest?


A
16 m
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B
24 m
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C
40 m
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D
56 m
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Solution

The correct option is A 16 m
x=40+12tt3
Velocity, v=dxdt=123t2
When particle comes to rest,
dxdt=v=0
123t2=03t2=12t=2 seconds
Distance travelled by the particle before coming to rest is
|x2x0|=|(40+12×223)(40+12×003)|=16 m
Hence, the correct answer is option (a).

Physics

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