Question

# A particle moves along parabolic path $$y = ax^{2}$$ in such a way that the x component of the velocity remains constant, say c. The acceleration of the particle is

A
ac^k
B
2ac2^j
C
ac2^j
D
a2c^j

Solution

## The correct option is B $$2ac^{2}\hat{j}$$Given that:acceleration along x = 0;i.e. $$\dfrac{dx}{dt} = c$$also given that $$y = ax^{2}$$differentiating with time.$$\dfrac{dy}{dt} = 2ax \dfrac{dx}{dt} = 2acx$$differentiating again we get $$a=2ac^2$$Physics

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