Question

# A particle moves in a circle of radius $$25\;\text{cm}$$ at two revolutions per second. The acceleration of the particle in $$m/s^2$$ is:

A
π2
B
8π2
C
4π2
D
2π2

Solution

## The correct option is A $$4\;\pi^2$$ Here $$T=\displaystyle\frac{1}{2}\text{sec}$$ the required centripetal acceleration for moving in a circle is $$\text{a}_{\displaystyle\text{c}}=\displaystyle\frac{\text{v}^2}{\text{r}}=\displaystyle\frac{(\text{r}\omega)^2}{\text{r}}=\text{r}\omega^2=\text{r}\times(2\pi/\text{T})^2$$ So $$\text{a}_{\displaystyle\text{c}}=0.25\times(2\pi/0.5)^2$$ $$\;\;\;\;\;\;\;\;\;\;=16\pi^2\times.25=4.0\pi^2$$Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More