A particle moves in a circle of radius 3.5 cm at a speed given by v=8t, where v is in cm/s and t in seconds. Find the tangential acceleration at t=2s. (in cm/s2)
A
8.0
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B
8.00
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C
8
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Solution
The tangential acceleration (at) is the rate of change of speed of particle moving on a circular path.
∵ speed of particle is given by v=8t cm ∴at=dvdt ⇒at=ddt(8t)=8 cm/s2
Here, tangential acceleration (at) is constant, it will not change with time.
Hence, tangential acceleration at t=2s is 8cm/s2.