Question

A particle moves in a circle of radius 5cm with constant speed and time period $0.2\pi s$.The acceleration of the particle is

• A. 15
• B. 25
• C. 36
• D. 5

Answer 1

Answer: (D)

5

Given,

$r=5cm=5\times {10}^{-2}m$

$T=0.2\pi s$

Velocity, $v=\frac{2\pi r}{T}$

$v=\frac{2\pi \times 5\times {10}^{-2}}{0.2\pi }=0.5m/s$

The centripetal acceleration of the particle in circular motion is given by

$a=\frac{v^2}{r}$

$a=\frac{0.5\times 0.5}{5\times {10}^{-2}}=5m/s^2$

The correct option is D.