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Byju's Answer

Standard XII

Physics

1st Equation of Motion

A particle mo...

Question

A particle moves rectilinearly with initial velocity $u$ and $a$ constant acceleration $a$ . The average velocity of the particle in a time interval from $t = 0$ to $t = t$ second of its motion is $u + x \times a t$ . find $4 x$ .

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Solution

$V_{a v g} = \frac{u t + \frac{1}{2} a t^{2}}{t} = u + \frac{1}{2} a t \Rightarrow x = 1 / 2$
$\Rightarrow 4 x = 2$

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A particle moves rectilinearly with initial velocity u and a constant acceleration a. The average velocity of the particle in a time interval from t=0 to t=t second of its motion is u+x×at . find 4x.

Vavg=ut+12at2t=u+12at⇒x=1/2⇒4x=2

A particle moves rectilinearly with initial velocity $u$ and $a$ constant acceleration $a$ . The average velocity of the particle in a time interval from $t = 0$ to $t = t$ second of its motion is $u + x \times a t$ . find $4 x$ .

$V_{a v g} = \frac{u t + \frac{1}{2} a t^{2}}{t} = u + \frac{1}{2} a t \Rightarrow x = 1 / 2$
$\Rightarrow 4 x = 2$