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A particle moves with a velocity 5¯i3¯j+6¯k m/s under the influence of a constant force F=(10¯i+10¯j+20¯k)N. The instantaneous power applied to the particle is
  1. 200 J/S
  2. 40 J/S
  3. 140 J/S
  4. 170 J/S


Solution

The correct option is C 140 J/S
p=F.V=(5¯i3¯j+6¯k).(10¯i+10¯j+20¯k)=5030+120=140J/S

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