A particle moves with a velocity v- - 5- - 3- - 6k- m-s- under the influence of a constant force F- - 10 - - 10 - - 20 k-N- The instantaneous power applied to the particleis-

The correct option is B 140 J/sWe know that power is defined as: P=F⃗·v⃗ Putting values will get, P=(5î 3ĵ+6k̂)·(10î+10ĵ+20k̂) P=50 30+120=140 J/s ...

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Standard XII

Physics

Equations of Motion

A particle mo...

Question

A particle moves with a velocity $¯ v = (5^i - 3^j + 6^k)$ m/s, under the influence of a constant force $\to F = (10^i + 10^j + 20^k) N$ . The instantaneous power applied to the particleis:

200 J/ s

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40 J/s

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140 J/s

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170 J/s

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Solution

The correct option is B 140 J/s
We know that power is defined as:
$P = \to F \cdot \to v$
Putting values will get,
$P = (5^i - 3^j + 6^k) \cdot (10^i + 10^j + 20^k)$

$P = 50 - 30 + 120 = 140 J / s$

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A particle moves with a velocity ¯v=(5^i−3^j+6^k) m/s, under the influence of a constant force →F=(10^i+10^j+20^k)N. The instantaneous power applied to the particleis:

The correct option is B 140 J/sWe know that power is defined as:P=→F⋅→vPutting values will get,P=(5^i−3^j+6^k)⋅(10^i+10^j+20^k)P=50−30+120=140J/s

A particle moves with a velocity $¯ v = (5^i - 3^j + 6^k)$ m/s, under the influence of a constant force $\to F = (10^i + 10^j + 20^k) N$ . The instantaneous power applied to the particleis:

The correct option is B 140 J/s
We know that power is defined as:
$P = \to F \cdot \to v$
Putting values will get,
$P = (5^i - 3^j + 6^k) \cdot (10^i + 10^j + 20^k)$

$P = 50 - 30 + 120 = 140 J / s$