A particle moves with a velocity- v-5-3-6k- m-s at an instant- under the influence of a constant force- F-10-10-20k- N- The instantaneous power applied to the particle is

We know that, instantaneous power, P=F·v ⇒ nbsp;P=(10î+10ĵ+20k̂) · (5î 3ĵ+6k̂) nbsp; ⇒ P=(10× 5)+(10× 3)+(20× 6) ⇒ P=140 W Hence, option (C) is the co ...

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Question

A particle moves with a velocity, $\to v = (5^i - 3^j + 6^k) m/s$ at an instant, under the influence of a constant force, $\to F = (10^i + 10^j + 20^k) N$ . The instantaneous power applied to the particle is

110 W

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120 W

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140 W

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150 W

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Solution

The correct option is C $140 W$
We know that, instantaneous power,

$P = \to F \cdot \to v$

$\Rightarrow P = (10^i + 10^j + 20^k) \cdot (5^i - 3^j + 6^k)$

$\Rightarrow P = (10 \times 5) + (10 \times - 3) + (20 \times 6)$

$\Rightarrow P = 140 W$

Hence, option $(C)$ is the correct answer.

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A particle moves with a velocity, →v=(5^i−3^j+6^k) m/s at an instant, under the influence of a constant force, →F=(10^i+10^j+20^k) N. The instantaneous power applied to the particle is

The correct option is C 140 WWe know that, instantaneous power, P=→F⋅→v ⇒P=(10^i+10^j+20^k)⋅(5^i−3^j+6^k) ⇒P=(10×5)+(10×−3)+(20×6) ⇒P=140 W Hence, option (C) is the correct answer.

A particle moves with a velocity, $\to v = (5^i - 3^j + 6^k) m/s$ at an instant, under the influence of a constant force, $\to F = (10^i + 10^j + 20^k) N$ . The instantaneous power applied to the particle is

The correct option is C $140 W$
We know that, instantaneous power,

$P = \to F \cdot \to v$

$\Rightarrow P = (10^i + 10^j + 20^k) \cdot (5^i - 3^j + 6^k)$

$\Rightarrow P = (10 \times 5) + (10 \times - 3) + (20 \times 6)$

$\Rightarrow P = 140 W$

Hence, option $(C)$ is the correct answer.