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Question

A particle moves with a velocity v=5^i3^j+6^kms1 under the influence of a constant force F=10^i+10^j+20^kN . The instantaneous power applied to the particle is


A

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B

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C

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D

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Solution

The correct option is C


P=F.v=(10^i+10^j+20^k).(5^i3^j+6^k)=5030+120=140Js1


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