A particle moves with a velocity v -7 -5 -6 k- ms -1 under the influence of a constant force F -10 -10 -20 k- N- Theinstantaneous power applied to the particle isA- 200 JS -1B- 40 JS -1C- 170 JS -4D- 140 JS -1

The correct option is D 140 JS 1 P̅=F̅.V̅ = ( 10 î+10ĵ+20k̂ ). ( 7î+5ĵ+6k̂ ) = 70 50+120 = 140Js^ 1 ...

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Standard XII

Physics

Normal Reaction

A particle mo...

Question

A particle moves with a velocity $\to v = (7^i - 5^j + 6^k) m s^{- 1}$ under the influence of a constant force $\to F = (10^i + 10^j + 20^k) N$ . The instantaneous power applied to the particle is

200 JS^-1

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40 JS^-1

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140 JS^-1

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170 JS^-4

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Solution

The correct option is C
140 JS^-1

$¯ P = ¯ F . ¯ V = (10^i + 10^j + 20^k) . (7^i + 5^j + 6^k) = 70 - 50 + 120 = 140 J s^{- 1}$

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A particle moves with a velocity →v=(7^i−5^j+6^k)ms−1 under the influence of a constant force →F=(10^i+10^j+20^k)N. The instantaneous power applied to the particle is

The correct option is C 140 JS-1 ¯P=¯F.¯V=(10^i+10^j+20^k).(7^i+5^j+6^k)=70−50+120=140Js−1

A particle moves with a velocity $\to v = (7^i - 5^j + 6^k) m s^{- 1}$ under the influence of a constant force $\to F = (10^i + 10^j + 20^k) N$ . The instantaneous power applied to the particle is

The correct option is C
140 JS^-1

$¯ P = ¯ F . ¯ V = (10^i + 10^j + 20^k) . (7^i + 5^j + 6^k) = 70 - 50 + 120 = 140 J s^{- 1}$