Question

a particle moving in a straight line has velocity and displacement equation as v = 4root(1+s). initial velocity of the particle is ?

Answer 1

Dear student,

The velocity of particle moving in straight line varies with its displacement as $v=4\sqrt{\left(1+s\right)}$
Now squaring on both sides we get,
$$\begin{gathered} v^2=4^2\left(1+s\right) \\ {v}^2=4^2+16s \\ comparingwiththeequation{v}^2=u^2+2asweget \\ {u}^2=16 \\ u=4m/s \end{gathered}$$

Regards.