Question

# A particle moving with a uniform acceleration travels 24 m and 64 m in the first two consecutive intervals of 4 sec each. Its initial velocity is

A
B
C
D

Solution

## The correct option is A Distance travelled in 4 sec 24=4u+12a×16......(i) Distance travelled in total 8 sec 88=8u+12a×64......(ii) After solving (i) and (ii), we get u = 1 ms.

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