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Question

A particle moving with a uniform acceleration travels 24 metre and 64 metre in first two successive intervals of 4 second each. Its initial velocity is

A
1m/s
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B
2m/s
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C
5m/s
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D
10m/s
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Solution

The correct option is A 1m/s
(v1+u2)t=24
v1+u=24×24=12
v1+u=12----------------(1)
(v2+v12)4=64
v1+v2=32---------------(2)
and (v2+42)8=88
v2+u=22----------------(3)
from (1) & (2)
12u+v2=32
v2u=20
from (3) & ()$
24=2
u=1m/s
Hence,
option (A) is correct answer.

1215486_1262693_ans_208604100bcc42f88fff0dfda167f855.JPG

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