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Question

A particle of charge q and velocity v passes undeflected though a space with non-zero electric field E and magnetic field B. The undeflecting conditions will hold if



Your Answer
A

signs of both q and E are reversed

Your Answer
B

signs of both q and B are reversed

Correct Answer
C

both B and E are doubled in magnitude

Your Answer
D

v=E/B


Solution

The correct option is C

both B and E are doubled in magnitude


Fe=qeB^nFe=qvB^(n)

Thus it both E and B are doubled the above conditions are not affected.

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