Question

A particle of charge q and velocity v passes undeflected though a space with non-zero electric field E and magnetic field B. The undeflecting conditions will hold if

A

signs of both q and E are reversed

B

signs of both q and B are reversed

C

both B and E are doubled in magnitude

D

v=E/B

Solution

The correct option is C both B and E are doubled in magnitude →Fe=qeB^n→Fe=qvB^(−n) Thus it both E and B are doubled the above conditions are not affected.

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