A particle of mass 0.3 kg is subjected to a force F = −kx with k = 15 N/m. What will be its initial acceleration if it is released from a point x = 20 cm?

Open in App

Solution

Displacement of the particle from the mean position, x = 20 cm = 0.2 m
k = 15 N/m
Mass of the particle, m = 0.3 kg
Acceleration, $a = \frac{|F|}{m}$
$\Rightarrow a = \frac{k x}{m} = \frac{15 (0.2)}{0.3} = \frac{3}{0.3} = 10 m / s^{2}$
So, the initial acceleration when the particle is released from a point x = 20 cm is 10 m/s².

Suggest Corrections

Similar questions

Q. A particle of mass 0.3 kg is subjected to a force

F = - k x

with

k = 15 \frac{N}{m}

. What will be the magnitude of its initial acceleration (

i n \frac{m}{s^{2}}

) if it is released from a point x=20 cm from its equilibrium position?

Particle of mass 0.3 kg is subjected to a force F = –kx with k = 15 N/m. What will be its initial acceleration if it is released from a point 20 cm away from the origin:

Q. A particle of mass

0.3 k g

is subjected to a force

F = - k x

with

k = 15 \frac{N}{m}

. What will be the magnitude of its initial acceleration (in

\frac{m}{s^{2}}

), if it is released from a point

x = 20 c m

from its equilibrium position?

Q. A particle of mass 0.3 kg is subjected to a force

F = - k x

with

k = 15 \frac{N}{m}

. What will be the magnitude of its initial acceleration (

i n \frac{m}{s^{2}}

) if it is released from a point x=20 cm from its equilibrium position?

Join BYJU'S Learning Program

A particle of mass 0.3 kg is subjected to a force F = −kx with k = 15 N/m. What will be its initial acceleration if it is released from a point x = 20 cm?

Displacement of the particle from the mean position, x = 20 cm = 0.2 m k = 15 N/m Mass of the particle, m = 0.3 kg Acceleration, a=Fm ⇒a=kxm=150.20.3=30.3=10 m/s2 So, the initial acceleration when the particle is released from a point x = 20 cm is 10 m/s2.