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A particle of mass 1 kg is projected from a tower of height 375 m with an initial velocity of 100 m/s at an angle 30 to the horizontal. Find its kinetic energy in joules just after the collision with ground if the collision is inelastic with e=12 (take g=10 m/s2).
1072929_856d9a84b4f54873be016ca78cc2f809.png

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Solution

tan30=VyVz
vertical and horizontal component of velocities are equal and the horizontal component of velocity always remain equals, therefore
Vz=100m/s
Vy=1003
K.E=me(Vy)r2mghm(Vz)22

1052131_1072929_ans_92c6b222032240d4a3e6f6ee3224d0e4.png

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