A particle of mass 10-3kg and charge 5- C is thrown at a speed of 20m s -1 against a uniform electric field of strength 2- 10 5 N C -1- The distance travelled by particle before coming to rest is-

The correct option is B 0.2m F=qE=5× 10 ^ 6 × 2× 10 ^ 5 =1N Since, the particle is thrown against the field ∴ a= F/m= 1 10 ^ 3 = 10 ^ 3 m s ...

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Standard X

Physics

Magnetic Field Due to Straight Current Carrying Conductor

A particle of...

Question

A particle of mass $10^{- 3} k g$ and charge $5 μ C$ is thrown at a speed of $20 m s^{- 1}$ against a uniform electric field of strength $2 \times 10^{5} N C^{- 1}$ . The distance travelled by particle before coming to rest is:

0.1 m

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0.2 m

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0.3 m

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0.4 m

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Solution

The correct option is B $0.2 m$
$F = q E = 5 \times 10^{6} \times 2 \times 10^{5} = 1 N$
Since, the particle is thrown against the field
$∴ a = - F / m = - \frac{1}{10^{- 3}} = - 10^{3} m s^{- 2}$
As $v^{2} - u^{2} = 2 a s$
$∴ 0^{2} - 20^{2} = 2 \times {(- 10}^{3}) \times s o r s = 0.2 m$

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A particle of mass 10−3kg and charge 5μC is thrown at a speed of 20ms−1 against a uniform electric field of strength 2×105NC−1. The distance travelled by particle before coming to rest is:

The correct option is B 0.2mF=qE=5×106×2×105=1NSince, the particle is thrown against the field∴a=−F/m=−110−3=−103ms−2As v2−u2=2as∴02−202=2×(−103)×sors=0.2m

A particle of mass $10^{- 3} k g$ and charge $5 μ C$ is thrown at a speed of $20 m s^{- 1}$ against a uniform electric field of strength $2 \times 10^{5} N C^{- 1}$ . The distance travelled by particle before coming to rest is:

The correct option is B $0.2 m$
$F = q E = 5 \times 10^{6} \times 2 \times 10^{5} = 1 N$
Since, the particle is thrown against the field
$∴ a = - F / m = - \frac{1}{10^{- 3}} = - 10^{3} m s^{- 2}$
As $v^{2} - u^{2} = 2 a s$
$∴ 0^{2} - 20^{2} = 2 \times {(- 10}^{3}) \times s o r s = 0.2 m$