Question

A particle of mass 200g executes simple harmonic motion. A restoring force is provided by a spring of spring constant 80N/m. Find the time period.

• A. 0.31 s
• B. 0.52 s
• C. 0.1 s
• D. 0.9 s

Answer 1

The correct option is A 0.31 s

The time period is $T=2\pi \sqrt{\frac{m}{k}}$
$=2\pi \sqrt{\frac{200\times {10}^{-3}kg}{80N{m}^{-1}}}$
$=2\pi \times 0.05s=0.31s.$