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Question

A particle of mass m and charge q is fastened to one end of a light string of length l. The other end of the string is fixed to the point O. The whole system lies on a frictionless horizontal plane. Initially, the mass is at rest at A. A uniform electric field in the direction shown is switched on. Then,
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A
the speed of the particle when it reaches B is 2qElm
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B
the speed of the particle when it reaches B is qElm
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C
the tension in the string when particles reaches B is 2qE
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D
the tension in the string when the particle reaches B is zero
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Solution

The correct options are
A the tension in the string when particles reaches B is 2qE
D the speed of the particle when it reaches B is qElm
Work done by tension = 0
Displacement=l(1cos600)
Work done by Electric field
=qE×l(1cos600)
(B) qEl2=12mV2V=qElm
(C) TqE=mV2lT=2qE

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