A particle of mass m is projected with a velocity v making an angle 45 degree with the horizontal. The magnitude of the angular momentum of the projectile about the pointof projection when the particle is at its max height h.
max height ,H= v2sin2θ/2g
velocity at max height = ux= vcosθ
angular momentum= muxH
and putting θ =450
angular momentum = mv3/g4√2