A particle P moves along a straight line away from a fixed point O obeying the relation S=16+48t−t3. The direction of P after t=4 is
A
Perpendicular to −−→OP
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B
−−→OP
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C
Rest at the instant
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D
−−→PO
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Solution
The correct option is D−−→PO Displacement is given by S(t)=16+48t−t3 V=dSdt=48−3t2
Clearly, for t>4,V<0
Negative sign indicates that it is moving towards the origin.