Question

# A particle starts from rest, accelerates at 2 m/s2 for 10s and then goes for constant speed for 30s and then decelerates at 2 m/s2  till it stops. What is the distance travelled by it800 m750 m700 m850 m

Solution

## The correct option is B 750 mVelocity acquired by body in 10 sec          v=0+2×10=20 m/s and distance travelled by it in 10 sec          S1=12×2×(10)2=100 m then it moves with constant velocity (20 m/s)     for 30 sec          S2=20×30=600 m After that due to retardation (4 m/s2) it stops S3=v22a=(20)22×4=50 m So total distance travelled is 750 m.

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