Question

# A particle starts from rest and has an acceleration of $$2m/{s}^{2}$$ for $$10sec$$. After that, it travels for $$30sec$$ with constant speed and then undergoes a retardation of $$4m/{s}^{2}$$ and comes back to rest. The total distance covered by the particle is

A
650m
B
700m
C
750m
D
800m

Solution

## The correct option is C $$750m$$$$v=20 m/s$$For region III,$$t=\dfrac{20}{4}=5$$secDistance covered is equal the area under velocity time graph$$\dfrac{1}{2} \times 10 \times 20+30\times 20+\dfrac{1}{2}\times 5\times 20$$$$s=750 m$$Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More