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Question

# A particle starts from rest with a time varying acceleration a=(2t−4). Here t is in s and a in m/s2. At what time, particle will have maximum velocity in negative direction?

A
3
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B
4
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C
2
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D
1
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Solution

## The correct option is C 2Acceleration – time graph of the particle is a straight line as shown in the figure. Area enclosed by the a−t graph and the x-axis gives the change in velocity . Since the area enclosed by a−t graph is negative up to t=2 s, change in velocity is also negative. Therefore, maximum velocity in negative direction will occur at t=2 s.

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